x^2-26x+44=0

Solution for x^2-26x+44=0 equation:

x^2-26x+44=0

a = 1; b = -26; c = +44;
Δ = b2-4ac
Δ = -262-4·1·44
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10\sqrt{5}}{2*1}=\frac{26-10\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10\sqrt{5}}{2*1}=\frac{26+10\sqrt{5}}{2}
$